按提交顺序收结果

（每道题开头都有同一段：上面的池小工具。）

贯穿全条的池小工具（标准库 ThreadPoolExecutor：固定 workers 个线程复用）：

pool_sum(fn, args, workers)     池对每个参数跑 fn，交回所有结果之和（和与顺序无关，确定）
pool_map(fn, args, workers)     map 按提交顺序回结果（顺序确定）
one_future(fn, x, workers)      提交一个任务，交回它的 Future 的 result()
submit_all(fn, args, workers)   提交全部，按提交顺序 result() 收结果
pool_peak(ntasks, workers) = min(ntasks, workers)   一次最多几个在跑
reuse(ntasks, workers) = (workers, ntasks)          池建几个线程 / 手写要建几个

池 workers=2，submit 了 [1,2,3] 的平方，按提交顺序 result() 收：

import concurrent.futures


def pool_sum(fn, args, workers):
    """用固定 workers 个线程的池，对每个参数跑 fn，交回所有结果之和（和与顺序无关，确定）。"""
    with concurrent.futures.ThreadPoolExecutor(max_workers=workers) as ex:
        return sum(ex.map(fn, args))


def pool_map(fn, args, workers):
    """池对每个参数跑 fn，map 按提交顺序回结果（顺序确定）。交回结果列表。"""
    with concurrent.futures.ThreadPoolExecutor(max_workers=workers) as ex:
        return list(ex.map(fn, args))


def one_future(fn, x, workers):
    """提交一个任务，交回它的 Future 的 result()。"""
    with concurrent.futures.ThreadPoolExecutor(max_workers=workers) as ex:
        fut = ex.submit(fn, x)
        return fut.result()


def submit_all(fn, args, workers):
    """提交全部，按提交顺序 result() 收结果（确定）。交回结果列表。"""
    with concurrent.futures.ThreadPoolExecutor(max_workers=workers) as ex:
        futs = [ex.submit(fn, a) for a in args]
        return [f.result() for f in futs]


def pool_peak(ntasks, workers):
    """池里一次最多几个任务在跑：worker 和任务里少的那个。"""
    return min(ntasks, workers)


def reuse(ntasks, workers):
    """跑 ntasks 个任务：线程池只建 workers 个线程复用；手写「一个任务一个线程」要建 ntasks 个。交回 (池建几个, 手写建几个)。"""
    return workers, ntasks


import queue
import threading


class Pool:
    """手写的简单线程池：几个 worker 循环从队列取任务、干完接着取；submit 提交，shutdown 放毒丸收工。"""
    def __init__(self, workers):
        self.workers = workers
        self.q = queue.Queue()
        self.results = []
        self.lock = threading.Lock()
        self.threads = [threading.Thread(target=self._work, daemon=True) for _ in range(workers)]
        for t in self.threads:
            t.start()

    def _work(self):
        while True:
            job = self.q.get()
            if job is None:            # 毒丸：收工
                return
            fn, x = job
            r = fn(x)
            with self.lock:
                self.results.append(r)

    def submit(self, fn, x):
        self.q.put((fn, x))

    def shutdown(self):
        for _ in range(self.workers):
            self.q.put(None)
        for t in self.threads:
            t.join(timeout=2)


def run_hand(fn, args, workers):
    """用手写池跑一批任务，交回 (结果之和, 一共处理了几个)。"""
    p = Pool(workers)
    for a in args:
        p.submit(fn, a)
    p.shutdown()
    return sum(p.results), len(p.results)


def due(events, now):
    """events: [(名字, 到点时刻)]；交回到 now 为止该跑的任务名（at <= now），按名字排。"""
    return sorted(name for name, at in events if at <= now)


def run_order(events):
    """按 (到点时刻, 名字) 排出执行顺序，交回名字列表——定时任务谁先跑是确定的。"""
    return [name for name, at in sorted(events, key=lambda e: (e[1], e[0]))]


def every(period, span):
    """一个每 period 跑一次的后台任务，在 [1, span] 时间里跑几次（span // period）。"""
    return span // period

def sq(x):
    return x * x


print(",".join(str(r) for r in submit_all(sq, [1, 2, 3], 2)))