换算成拍数差多少

运行下面这段程序，填写它打印出来的结果。

STAGES = 5

def one_by_one(n):
    return n * STAGES

def pipelined(n):
    return n + STAGES - 1

def wrong_guesses(pattern):
    last = -1
    wrong = 0
    for t in pattern:
        if last == -1 or t != last:
            wrong = wrong + 1
        last = t
    return wrong

FLUSH = 3
raw = [1, 0, 1, 1, 0, 0, 1, 0]
sortd = sorted(raw)
a = pipelined(8) + wrong_guesses(raw) * FLUSH
b = pipelined(8) + wrong_guesses(sortd) * FLUSH
print(str(a) + "/" + str(b) + "/" + str(round(a / b, 2)))