两个核轮流改同一块

运行下面这段程序，填写它打印出来的结果。

BLK = 4

def traffic(seq):
    owner = -1
    moves = 0
    for core, addr in seq:
        b = addr // BLK
        if owner != core:
            moves = moves + 1
            owner = core
    return moves

same = [(0, 0), (1, 1), (0, 0), (1, 1)]
apart = [(0, 0), (0, 0), (1, 1), (1, 1)]
print(str(traffic(same)) + "/" + str(traffic(apart)))