扫两遍和扫一遍，搬了几趟

运行下面这段程序，填写它打印出来的结果。

BLK = 4

def loads(idxs):
    cur = -1
    n = 0
    for i in idxs:
        b = i // BLK
        if b != cur:
            n = n + 1
            cur = b
    return n

idxs = list(range(32))
two_pass = loads(idxs) * 2
one_pass = loads(idxs)
print(str(two_pass) + "/" + str(one_pass) + "/"
      + str(two_pass // one_pass))