目录上三位各管什么

运行下面这段程序，填写它打印出来的结果。

def cls(uid, gid, f_uid, f_gid):
    if uid == f_uid:
        return 0
    if gid == f_gid:
        return 1
    return 2

def can(mode, k, op):
    digit = (mode >> (3 * (2 - k))) & 7
    bit = {"r": 4, "w": 2, "x": 1}[op]
    return digit & bit != 0

d = 0o644
k = 0
list_names = can(d, k, "r")
go_through = can(d, k, "x")
create = can(d, k, "w")
print(str(list_names) + "/" + str(go_through) + "/" + str(create))