谁能读,谁不能
运行下面这段程序,填写它打印出来的结果。
def cls(uid, gid, f_uid, f_gid):
if uid == f_uid:
return 0
if gid == f_gid:
return 1
return 2
def can(mode, k, op):
digit = (mode >> (3 * (2 - k))) & 7
bit = {"r": 4, "w": 2, "x": 1}[op]
return digit & bit != 0
# 文件属主 uid=1000、属组 gid=1000,权限 640
mode = 0o640
me = can(mode, cls(1000, 1000, 1000, 1000), "r")
mate = can(mode, cls(1001, 1000, 1000, 1000), "r")
other = can(mode, cls(1002, 1002, 1000, 1000), "r")
print(str(me) + "/" + str(mate) + "/" + str(other))
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