补全：写出 record

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（每道题开头都有同一段游戏核心：new_round 开一局、parse 校验输入、judge 比大小、step 记一次猜测、score 算分。秘密固定是 73。）

补全 record(rec, st)：局数加一、赢了 wins 加一、总分累加、最高分取大。输出四个数。

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← 补全：写出 score 补全：把记录写成文本再读回 →

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代码编辑器

语言： Ctrl + Enter 运行

LIMIT = 7

def new_round(secret):
    return {"secret": secret, "tries": 0, "low": 1, "high": 100, "over": False, "won": False}

def parse(line):
    s = line.strip()
    if s in ("q", "r"):
        return s
    if not s.isdigit():
        return None
    n = int(s)
    if n < 1 or n > 100:
        return None
    return n

def judge(secret, n):
    if n > secret:
        return "大了"
    if n < secret:
        return "小了"
    return "对了"

def step(st, n):
    st["tries"] += 1
    r = judge(st["secret"], n)
    if r == "大了" and n - 1 < st["high"]:
        st["high"] = n - 1
    if r == "小了" and n + 1 > st["low"]:
        st["low"] = n + 1
    if r == "对了":
        st["won"] = True
    if st["won"] or st["tries"] >= LIMIT:
        st["over"] = True
    return r

def score(st):
    return LIMIT + 1 - st["tries"] if st["won"] else 0

def play(secret, lines):
    st = new_round(secret)
    out = []
    for line in lines:
        if st["over"]:
            break
        n = parse(line)
        if n is None:
            out.append("无效")
            continue
        if n == "q":
            out.append("退出")
            break
        out.append(step(st, n))
    return st, out

def record(rec, st):
    # TODO: rounds / wins / total / best
    return score(st)

SECRETS = [73, 18, 91]
ROUNDS = [["50", "75", "62", "68", "71", "73"],
          ["50", "25", "12", "18"],
          ["50", "25", "12", "6", "3", "1", "2"]]
rec = {"rounds": 0, "wins": 0, "total": 0, "best": 0}
for secret, lines in zip(SECRETS, ROUNDS):
    st, msgs = play(secret, lines)
    record(rec, st)
print(str(rec["rounds"]) + "/" + str(rec["wins"]) + "/" + str(rec["total"]) + "/" + str(rec["best"]))

本次输入：

输出：

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补全：写出 record

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